Everything of genius is simple.
P[10(k-1),10k]={p: p prime number, 10(k-1)<p<10k}, k=1,2,3...;
P[1,10n]=U1n P[10(k-1),10k)];
п(x)=card{p: p prime number, p<=x};
Theorem. п(10n)<=4n, n=1,2,3,...; card P[10(k-1),10k]<=4, k=1,2,3,...
p r o v e
card P[10(k-1),10k]<=4, k=1,2,3,...; because of p=1(mod 10) or p=3(mod 10) or p=7(mod 10) or p=9(mod 10), when p>2 and p<> 5.
п(10n)=card P[1,10n]=card U1n P[10(k-1),10k]=SUM1n card P[10(k-1),10k]<=SUM1n 4=4n.
Emzari Papava
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